0.5=0.16x^2/3

Solution for 0.5=0.16x^2/3 equation:

0.5=0.16x^2/3

We move all terms to the left:

0.5-(0.16x^2/3)=0

We get rid of parentheses

-0.16x^2/3+0.5=0

We multiply all the terms by the denominator


-0.16x^2+(0.5)*3=0

We add all the numbers together, and all the variables

-0.16x^2+1.5=0

a = -0.16; b = 0; c = +1.5;
Δ = b2-4ac
Δ = 02-4·(-0.16)·1.5
Δ = 0.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.96}}{2*-0.16}=\frac{0-\sqrt{0.96}}{-0.32}
=-\frac{\sqrt{}}{-0.32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.96}}{2*-0.16}=\frac{0+\sqrt{0.96}}{-0.32}
=\frac{\sqrt{}}{-0.32}
$